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-16t^2+135.37t+4=0
a = -16; b = 135.37; c = +4;
Δ = b2-4ac
Δ = 135.372-4·(-16)·4
Δ = 18581.0369
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(135.37)-\sqrt{18581.0369}}{2*-16}=\frac{-135.37-\sqrt{18581.0369}}{-32} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(135.37)+\sqrt{18581.0369}}{2*-16}=\frac{-135.37+\sqrt{18581.0369}}{-32} $
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